C Program to Print Digit in Word

If a digit given then this C program prints or displays it in word. For example if a digit '4' is given this program prints in word 'four', if digit '5' is given it prints 'five' and so on for remaining digits.

C Program to Print Given Digit in Word

/* C Code to print digit in word */

#include<stdio.h>
int main()
{
	int digit;
 
	printf("\n \n Enter any digit in between 0-9: ");
	scanf("%d",&digit);

	switch(digit)
	{
	case 0:
	printf("\n The number you entered is 'zero' \n \n");
	break;
 
	case 1:
	printf("\n The number you entered 'one' \n \n");
	break;
 
	case 2:
	printf("\n The number you entered 'two' \n \n");
	break;
 
	case 3:
	printf("\n The number you entered 'three' \n \n");
	break;
 
	case 4:
	printf("\n The number you entered 'four' \n \n");
	break;
 
	case 5:
	printf("\n The number you entered 'five' \n \n");
	break;

	case 6:
	printf("\n The number you entered 'six' \n \n");
	break; 

	case 7:
	printf("\n The number you entered 'seven' \n \n");
	break;

	case 8:
	printf("\n The number you entered 'eight' \n \n");
	break;
 
	case 9:
	printf("\n The number you entered 'nine' \n \n");
	break;

	default:
	printf("\n You haven't enetered digit from 0-9 \n \n");

	}
    return 0;
}

Output:

Test Case 1:

 Enter any in between 0-9: 0

 The number you entered is 'zero'
 
Test Case 2:
 
 Enter any in between 0-9: 1

 The number you entered 'one'
 
Test Case 3:
 
 Enter any in between 0-9: 2

 The number you entered 'two'
 
Test Case 4:

 Enter any in between 0-9: 9

 The number you entered 'nine'

Explanation:

Accept a digit from user to print it in word. We are storing the digit in variable named digit. Then we are passing the value of digit to switch case and depending on the value of digit variable corresponding case gets executed and given digit is displayed in word.